Homework Help: physics

Posted by Anonymous on Tuesday, March 6, 2012 at 3:21pm.

power supply has an open-circuit voltage of 39.0 V and an internal resistance of 2.00 Ù. It is used to charge two storage batteries connected in series, each having an emf of 5.50 V and internal resistance of 0.300 Ù. The charging current is to be 3.30 A.

physics - Henry, Wednesday, March 7, 2012 at 4:46pm
I=(E-(5.5+5.5)) / (2+0.3+0.3) = 3.30 A.
(E-11) / 2.6 = 3.30.
E-11 = 8.58.
E = 8.58 + 11 = 19.58 Volts=Voltage
setting required for a charging current of 3.30 amps.

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