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March 30, 2015

March 30, 2015

Posted by **Jessica** on Tuesday, March 6, 2012 at 2:11pm.

2. Determine the minimum value of the function f(x)= e^(-x) - 2e^x on the interval -1≤x≤2.

- Calculus -
**Steve**, Tuesday, March 6, 2012 at 2:54pmyou know that any local min/max must occur where f' = 0.

f' = ln5 * 5^x - 4x^2

That occurs at about x=-.5 and 1.24

So, check f(x) at the endpoints of the interval, and at those two values.

Looks to me like max is at x=1.24, min at x=2

Treat the other similarly.

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