Two children sit on a seesaw that is 14 ft long. One child weighs 95 lb, and the other child weighs 69 lb. If x is the distance of the 69-pound child from the fulcrum when the seesaw balances, state the value of each of the other variables in the lever-system formula F1x = F2(d – x), and solve for that distance. (Round your answers to two decimal places.)

To solve this problem, we can use the lever-system formula F1x = F2(d – x), where:

- F1 is the force exerted by the first child (95 lb),
- F2 is the force exerted by the second child (69 lb),
- x is the distance of the 69-pound child from the fulcrum, and
- d is the length of the seesaw (14 ft).

We can start by plugging in the known values into the formula:

95x = 69(14 - x)

Next, we can solve for x by simplifying and rearranging the equation:

95x = 69(14 - x)
95x = 69*14 - 69x
95x + 69x = 69*14
(95 + 69)x = 69*14
164x = 69*14
x = (69*14) / 164
x ≈ 5.89 ft

So, the distance of the 69-pound child from the fulcrum when the seesaw balances is approximately 5.89 ft.