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April 24, 2014

Homework Help: Chemistry

Posted by David on Monday, March 5, 2012 at 10:52pm.

At equilibrium, the concentrations in this system were found to be [N2] = [O2] = 0.100 M and [NO] = 0.500 M.
N2(g) + O2(g) <-> 2NO(g)
If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium is re-established?

Kc = 0.800 M/[0.100M][0.100M] = 80 M?

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