Posted by Tracy on .
If someone could please be kind enough to see me through this problem?
Calculate the value of Kp for the equation C(s) + CO2(g) <> 2CO(g) Kp?
Given that at a certain temperature..
C(s) + 2H2O(g) <> CO2(g) + 2H2(g) Kp1 = 3.03 and
H2(g) + CO2(g) <> H2O(g) + CO(g) Kp2 = 0.637
i sq rooted the last equation: (0.637)^2 = 0.405769 and then multiplied by 3.03 = 1.2294
is that correct?

Chemistry 
DrBob222,
I think what you want to do is multiply equation 1 by 2 and add to equation 2. I believe that will give you the equation you want. To find the Kp value, it will be (Kp1)^2*Kp2 = ?

Chemistry 
Tracy,
Hi Dr. Bob,
(3.03)^2 * 0.637 = 5.85?
What would I do with the first equation that i got? 
Chemistry 
Tracy,
OHH (2.567)^2*0.637 = 4.197?!
.. or was that a fail epiphany 
Chemistry 
DrBob222,
If I take the square root of 3.03*0.637 I don't get 4.197.

Chemistry 
joe,
is this answer correct? these form need to verify is these answers are correct. ty