Posted by DCM on Monday, March 5, 2012 at 9:40pm.
The image formed by the first lens acts as the object for the second lens. For the location of the first lens image,
1/di = 1/f - 1/do = 1/12.2 - 1/35 = 0.0534
do = 18.73 cm. That places it 4.67 cm in front of the second lens.
For the second lens,
1/4.67 + 1/di = 1/12.2
di = -7.57 cm
The final image is 7.57 cm to the left of the second lens, in the region between the lenses.
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