Posted by Tracy on Monday, March 5, 2012 at 8:25pm.
1 and 2 ok.
3 is no.
Decreasing the volume means increasing pressure. When pressure is increased the reaction shifts to the side with smaller number of gaseous moles. You have 3 moles on left and 2 on the right; therefore, it shifts to the right.
Ohh i understand Dr. Bob. So in terms of adding more.. would that be the same as increasing concentration? For example:
S(s) + O2(g) <-> SO2
1] how will adding more S(s) shift the equilibrium?
a] to the right [this?]
b] to the left
c] no effect
2] How will removing some SO2(g) shift the equilibrium?
a] to the right [this?]
b] to the left
c] no effect
3] How will decrasing the volume of the container shift the equilibrium?
a] to the right [thissss!]
b] to the left
c] no effect
ohhh it was no effect and no effect for 1 and 3 i got it
Remember solids, the sulfur in this case, doesn't enter into the K expression. Adding another bit of S or taking a little out won't change the equilibrium. And for the pressure change, you have 1 mole gas on the left and 1 mole on the right so there is no effect.
Related Questions
chemistry - at a particular temperature, k equals 2.0 x 10 to the -6 power for ...
Chemistry - Estimate the value of the equilibrium constant at 550 K for each of ...
Chemistry - At 2000°C, 5.0×10-3 mol CO2 is introduced into a 1.0 L ...
Chemistry/Equilibrium calculations - At 1200 K, the approximate temperature of ...
Chemistry - At 1200 K, the approximate temperature of vehicle exhaust gases, Kp ...
chemistry - Can anyone explain Le Chatelier's principal? How you know when ...
chemistry - When carbon dioxide is heated in a closed container, it decomposes ...
chemistry - Gaseous CO2 decomposes to form the gaes CO and O2. At 20.0 degrees ...
CHEMISTRY - calculate the delta h for the reaction 2C+2H--> C2H4 C+O2--&...
chemistry - When carbon dioxide is heated in a closed container, it decomposes ...
For Further Reading
