Posted by **Jessica** on Monday, March 5, 2012 at 8:13pm.

What values of x is there an absolute minimum for the function y= -1/3x^2 + 2x?

I found the derivative of the function which is y'=-2/3x + 2

set it to 0=y'=-2/3x + 2

x=3

What do I do now?

- Calculus -
**bobpursley**, Monday, March 5, 2012 at 8:19pm
what is the second derivative of y?

y"=-2/3, which means that the curve is downward, so that is a maximum...

The curve is a parabola, with a max at (x=3), and has no absolute min.

- Calculus -
**Jessica**, Monday, March 5, 2012 at 8:33pm
Thank you!

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