March 1, 2017

Homework Help: Calculus

Posted by Jessica on Monday, March 5, 2012 at 8:13pm.

What values of x is there an absolute minimum for the function y= -1/3x^2 + 2x?

I found the derivative of the function which is y'=-2/3x + 2

set it to 0=y'=-2/3x + 2

What do I do now?

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