Saturday

December 20, 2014

December 20, 2014

Posted by **Jessica** on Monday, March 5, 2012 at 8:13pm.

I found the derivative of the function which is y'=-2/3x + 2

set it to 0=y'=-2/3x + 2

x=3

What do I do now?

- Calculus -
**bobpursley**, Monday, March 5, 2012 at 8:19pmwhat is the second derivative of y?

y"=-2/3, which means that the curve is downward, so that is a maximum...

The curve is a parabola, with a max at (x=3), and has no absolute min.

- Calculus -
**Jessica**, Monday, March 5, 2012 at 8:33pmThank you!

**Answer this Question**

**Related Questions**

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...

Calculus - Find the absolute maximum and absolute minimum values of the function...

Calculus - another question - "Find the absolute minimum value of the function f...

Calculus - Find the extreme value(s) of the function f(x)=1/(1-x^2). I tried, ...

Applied Calculus - Find the absolute maximum and absolute minimum values, if any...

Calculus - The function f(x)=(x^4)-(10x^3)+(18x^2)-8 is continuous on the closed...

Calculus Grade 12 University - Determine the critical numbers and find the ...

Calculus - A cubic polynomial function f is defined by f(x) = 4x^3 + ax^2 + bx...

Calculus - A cubic polynomial function f is defined by f(x) = 4x^3 + ax^2 + bx...