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An electron in a cathode-ray-tube (CRT) accelerates from 20300 m/s to 3.99 × 106 m/s over 1.34 cm.
How long does the electron take to travel this distance?

  • physics - ,

    (Vf^2-Vi^2)/(2(deltax)) so ((3.9910^6)^2-(20300)^2)/(2(0.0134)) which equals 5.9 x 10^14

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