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physics

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A ball starts from rest and rolls down a hill with uniform acceleration, traveling 170 m during the second 5.5 s of its motion.


How far did it roll during the first 5.5 s of motion?
Express your answer using two significant figures.

x= m

  • physics -

    Speed at middle of second 5.5 s interval = 3 x (Speed at middle of first 5.5 s interval) = 170/5.5 = 30.91 m/s
    = (average speed during that interval)

    Speed at 8.25 s = 3 x speed at 2.75 s.
    Therefore:
    speed at 2.75 s = (1/3)*30.91 = 10.30 m/s
    Distance travelled during first interval 10.30 x 5.5 = 56.65 m
    Rounding that two 2 significant figures gives 57 m.

  • maths -

    plzzz explain how to draw root 5 on a number line

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