Posted by L.Bianchessi on Monday, March 5, 2012 at 3:47pm.
You ALWAYS start with one or all of the following:
1. balanced equation
2. ICE chart
3. think in terms of mols.
pH = 10.88 so pOH = 3.12 and OH^- = 7.58E-4
M..........BOH ==> B^+ + OH^-
initial.0.035M.....0......0
change..7.58E-4..7.58E-4..7.58E-4
equil..0.035-7.58E-4....etc
Kb = (B^+)(OH^-)/(BOH)
Substitute from the ICE chart and solve for Kb. Note that 0.035-7.58E-4 is not = 0.035
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