Posted by Priscilla on .
I wanted to calculate the average equivalent weight of an unknown acid for an acidbase titration experiment. The mass of the unknown that I had to obtain is 0.2 g and the equivalents of the acid is .001046 L x N. But is this equation right? Does the equivalent mass equal to the mass of the solid acid divided by the number of equivalents of acid? If so, isn't the average eq. wt. too high?
Thank you so much for any help.

Chemistry 
DrBob222,
liters x normality x equivalent weight = grams.

Chemistry 
Priscilla,
wait, liters x normality = grams because I wanted to find the equivalent wt

Chemistry 
Priscilla,
Wait, im not making sense. I know liters x normality gives you the equivalents of an acid. But are you sure it's not the grams I obtained divided by the equivalents of the acid.

Chemistry 
DrBob222,
Of course it is but that's what I wrote in a different form.
liters x normality x eq wt = grams.
liters x normality = # equiv so
#eq x eq wt = grams and
eq wt = grams/#equivalents
I like
liters x normality x equivalent weight = grams BECAUSE it solve one equation instead of three and get the same answer. 
Chemistry 
Priscilla,
ok, thank you very much for your time and patience. I understand, im sorry if I bothered you too much. But thanks a lot.