If 6.02 moles of potassium react with a 0.8 M silver acetate solution, how many L of silver acetate are needed?
See your post above.
To find out how many liters of silver acetate are needed, we will use the given information and perform a calculation using the formula:
Volume (in liters) = moles of substance / molarity of solution
First, let's calculate the number of moles of silver acetate required. We will use the mole ratio from the balanced chemical equation:
2 K + 2 Ag(C2H3O2) → 2 Ag + 2 K(C2H3O2)
From the equation, we see that 2 moles of silver acetate are required for every 2 moles of potassium. Since we have 6.02 moles of potassium, we will need 6.02 moles of silver acetate.
Now, let's calculate the volume of silver acetate solution required. We will use the given molarity of the silver acetate solution, 0.8 M:
Volume (in liters) = moles of substance / molarity of solution
Volume = 6.02 moles / 0.8 M
Volume = 7.525 liters
Therefore, you would need approximately 7.525 liters of the 0.8 M silver acetate solution to react with 6.02 moles of potassium.