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April 1, 2015

April 1, 2015

Posted by **Erica** on Monday, March 5, 2012 at 1:58pm.

Day 1 1 tile

Day 2 5 tiles

Day 3 13 tiles

- Math -
**Susan**, Monday, March 5, 2012 at 2:23pm1+4(n-1) where n is the day number

on day 10

1+4(10-1)=37

on day fifty

1+4(50-1)=197

- Math -
**Steve**, Monday, March 5, 2012 at 3:52pmDay 3 does not fit: 1+4*2 = 9

Since the difference is changing by 4 each day, we will have a quadratic:

Day n: 2n^2 - 2n + 1

- Math -
**Sandro**, Friday, April 27, 2012 at 5:50pmWhat do you mean by the ^ in your equation Steve? I don't really understand the 2n^2-2n+1. I did figure out it was a quadratic equation, and actually happened to figure out the entire problem until I noticed it said "Write a description or formula that allows me to figure out the number of tiles for any day number?"

- Math -
**Sandro**, Friday, April 27, 2012 at 6:21pmOh, ok, do you mean to cube the first number by the 2nd, get back to me... Thnx

- Math -
**Sandro**, Friday, April 27, 2012 at 7:09pmSteve is wrong!!! D:

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