Concentrated acetic acid, HC2H3O2 is 17.4 M. How many mL of concentrated acetic acid do you need to prepare 125 mL of a 0.150 M solution of acetic acid?
M1V1 = M2V2
To determine how many mL of concentrated acetic acid are required to prepare the desired solution, we can use the dilution formula:
C1 * V1 = C2 * V2
Where:
C1 = initial concentration of the concentrated solution (in M)
V1 = volume of the concentrated solution (in mL)
C2 = final concentration of the diluted solution (in M)
V2 = final volume of the diluted solution (in mL)
Given:
C1 = 17.4 M
V1 = ?
C2 = 0.150 M
V2 = 125 mL
Now, let's rearrange the formula to solve for V1:
V1 = (C2 * V2) / C1
Substituting the given values:
V1 = (0.150 M * 125 mL) / 17.4 M
V1 ≈ 1.08 mL
Therefore, you would need approximately 1.08 mL of the concentrated acetic acid to prepare 125 mL of a 0.150 M solution of acetic acid.