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October 20, 2014

October 20, 2014

Posted by **amir** on Sunday, March 4, 2012 at 9:51pm.

- calculus -
**MathMate**, Sunday, March 4, 2012 at 11:53pmTo find if f(x) is concave up, we calculate the sign f"(x).

The interval on which f"(x)>0 is concave up, and vice versa.

Let f(x)=cos²(x),

f'(x)=-2sin(x)cos(x)

f"(x)=-2cos(2x)

Now plot f"(x) between 0 and 2π to get:

f"(x)≥0 for x∈[-π/4,π/4]

f"(x)≤0 for x∈[π/4,3π/4]

f"(x)≥0 for x∈[3π/4,5π/4]

f"(x)≤0 for x∈[5π/4,7π/4]

...

Can you take it from here?

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