Posted by Malika on Sunday, March 4, 2012 at 9:51pm.
Find the point on the graph of the function that is closest to the given point.
Function Point
f(x) = x^2 (16, 1/2)
(x, y) = ( ) ?

Math  drwls, Monday, March 5, 2012 at 8:52am
Let D be the distance from a point on the function line from (16, 1/2)
D^2 = (x16)^2 + (y  1/2)^2
= (x16)^2 + (x^2 1/2)^2
When this is a minimum, dD^2/dx = 0
2(x16)+ 2(x^2 1/2)*2x = 0
2x  32 + 4x^3 2x = 0
4x^3 = 32
x = +/ 2
y = 4

Math  Malika, Monday, March 5, 2012 at 11:27am
Thanks :)
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