Posted by **SAM** on Sunday, March 4, 2012 at 2:41pm.

Yesterday, at a local restaurant, 60% of the customers ordered a burger.

If 42% of the customers ordered a burger and fries, what is the probability that a customer who ordered a burger also ordered fries?

If 15% of the customers ordered a burger and onion rings, what is the probability that a customer ordered onion rings given that he/she ordered a burger?

- MATH! :( Conditional Probability -
**MathMate**, Sunday, March 4, 2012 at 3:27pm
The conditional probability of event A happening given B is given by

P(A|B) = P(A∩B)/P(B)

In the example,

B=customers ordered burgers

P(B)=0.60

F=customers ordered Fries

P(B∩F)=0.42

So probability of ordering fries given the customer ordered a burger is

P(F|B)=P(B∩F)/P(B)=0.42/0.6=0.7

and similarly

R=customers ordered onion Rings

P(B∩R)=0.15

What is

P(R|B)?

## Answer This Question

## Related Questions

- Logical Reasoning - Ted is ordering food at a restaurant. One of the ways to ...
- Art - What message was the designer of this hamburger ad hoping to send with the...
- math - One weekend, there were 95 pizzas ordered for the sophomore dorm. That ...
- math - A burger restaurant advertises that there are 96 possible ways to order ...
- Correct grammer - Pick the correct answer which corrects the underlined portion ...
- Math - On Saturday, 124 customers went into the Sandwich Shop. Of those ...
- Math - Of the recent customers at Burger Haven, 12 wanted cheese on their ...
- math - .25 lb burger costs $2.95 .50 lb burger costs $3.90 how much does a pound...
- math 5th grade - One morning, 8/9 of the customers at the diner ordered coffee. ...
- math 5th grade - One morning, 8/9 of the customers at the diner ordered coffee. ...

More Related Questions