Posted by SAM on Sunday, March 4, 2012 at 2:41pm.
Yesterday, at a local restaurant, 60% of the customers ordered a burger.
If 42% of the customers ordered a burger and fries, what is the probability that a customer who ordered a burger also ordered fries?
If 15% of the customers ordered a burger and onion rings, what is the probability that a customer ordered onion rings given that he/she ordered a burger?

MATH! :( Conditional Probability  MathMate, Sunday, March 4, 2012 at 3:27pm
The conditional probability of event A happening given B is given by
P(AB) = P(A∩B)/P(B)
In the example,
B=customers ordered burgers
P(B)=0.60
F=customers ordered Fries
P(B∩F)=0.42
So probability of ordering fries given the customer ordered a burger is
P(FB)=P(B∩F)/P(B)=0.42/0.6=0.7
and similarly
R=customers ordered onion Rings
P(B∩R)=0.15
What is
P(RB)?
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