Posted by **SAM** on Sunday, March 4, 2012 at 2:41pm.

Yesterday, at a local restaurant, 60% of the customers ordered a burger.

If 42% of the customers ordered a burger and fries, what is the probability that a customer who ordered a burger also ordered fries?

If 15% of the customers ordered a burger and onion rings, what is the probability that a customer ordered onion rings given that he/she ordered a burger?

- MATH! :( Conditional Probability -
**MathMate**, Sunday, March 4, 2012 at 3:27pm
The conditional probability of event A happening given B is given by

P(A|B) = P(A∩B)/P(B)

In the example,

B=customers ordered burgers

P(B)=0.60

F=customers ordered Fries

P(B∩F)=0.42

So probability of ordering fries given the customer ordered a burger is

P(F|B)=P(B∩F)/P(B)=0.42/0.6=0.7

and similarly

R=customers ordered onion Rings

P(B∩R)=0.15

What is

P(R|B)?

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