Posted by John on Sunday, March 4, 2012 at 2:31pm.
the anti derivative is (m/2)x^2 - 1/3(x)^3 so if you use the 2nd fundamental theorem of calculus using (mx - x^2) over the interval (0,m) and set that equal to 8 (the interval is 0 to m because the function with the larger area is mx) you should get m^3 / 8 = 8. Solve for m and you're done :)
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