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November 21, 2014

November 21, 2014

Posted by **John** on Sunday, March 4, 2012 at 2:31pm.

bounded by the curves y = x^2 and y = mx is equal to 8.

I would very much appreciate it if someone could find the answer and explain how you did it.

- calculus -
**Abby**, Wednesday, March 6, 2013 at 12:25amthe anti derivative is (m/2)x^2 - 1/3(x)^3 so if you use the 2nd fundamental theorem of calculus using (mx - x^2) over the interval (0,m) and set that equal to 8 (the interval is 0 to m because the function with the larger area is mx) you should get m^3 / 8 = 8. Solve for m and you're done :)

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