Posted by Student on Sunday, March 4, 2012 at 2:02pm.
P(at least 4 correct)
= P(4 correct) + P(5 correct) + P(6 correct)
= 6C4 (½)^4 (½)^2 + 6C5 (½)^5 (½)^1 + 6C6 (½)^6 (½)^0
... four correct answers, two incorrect, in any order plus five correct answers, one incorrect, in any order, plus six correct answers, zero incorrect, and only one possible order ...
= 15 (½)^6 + 6 (½)^6 + 1 (½)^6
= (15+6+1) / (2^6)
= 22 / 64
= 11 / 32
= 0.34375
How did you get this?
= 6C4 (½)^4 (½)^2 + 6C5 (½)^5 (½)^1 + 6C6 (½)^6 (½)^0
?
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