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September 18, 2014

September 18, 2014

Posted by **Lauren** on Sunday, March 4, 2012 at 6:13am.

For ice, use a specific heat of 2.01 J/(g*degrees C) and delta H_fus = 6.01 kJ/mol.

- chemistry -
**DrBob222**, Sunday, March 4, 2012 at 12:21pmHow much heat is needed to raise the temperature of ice at -11.2 C to 0 C? That will x grams x 2.01 J/g*C x 11.2 = 22.51x.

How much heat is needed to melt the ice?

That will be xgrams x 333.6 J/g = 333.6x.

How much heat is needed to raise the temperature from 0C to 29.8.

That will be x grams x 4.186 x (29.8) = 124.7x

Total = 124.7x + 22.51x + 333.6x = ?x

?x = 4120J

Solve for x.

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