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February 1, 2015

February 1, 2015

Posted by **Jake** on Saturday, March 3, 2012 at 11:11pm.

How did the book get answer max t=3 and min t=1

- Math -
**Susan**, Sunday, March 4, 2012 at 8:31amFind the derivative using the quotient rule

C'=(.1(t+3)^2-(2t+6)(.1t))/(t+3)^4

find where .1(t+3)^2 - (2t+6)(.1t) = 0

solving for t

t = 3

Evaluate C(1)

C(3) and C(6)

C(3) gives the maximum value, C(1) gives the minimum

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