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An object moves in a straight line. Its velocity, in m/s, at time t is v(t)=4t^2/(1+t^2),t≥0.

Determine the maximum and minimum velocities on the interval 1≤x≤4.

The answer says min. velocity is 0m/s but has no maximum?

  • Calculus -

    If x≤ 4 it should have a max at 4
    If x<4 there is no max

  • Calculus -

    since v'(t) = 8t/(1+t^2)^2
    v' > 0 for 1<=t<=4

    since v is increasing on the interval,

    max v is at t=4
    min v is at t=1

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