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March 30, 2015

March 30, 2015

Posted by **Katie** on Saturday, March 3, 2012 at 5:37pm.

- Trig -
**Steve**, Sunday, March 4, 2012 at 11:28amsin/(cos+1) + (cos-1)/sin

= [sin*sin + (cos-1)(cos+1)]/[sin(cos+1)]

= (sin^2 + cos^2 - 1)/[sin(cos+1)]

= (1-1)/[sin(cos+1)]

= 0

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