Friday

June 24, 2016
Posted by **Daniel** on Saturday, March 3, 2012 at 5:14pm.

x^y = y^x

I was wondering if I was right in the steps I was taking

first was to take the Ln or both sides making it

y Ln(x) = x Ln(y)

then just taking the derivatives of both sides using product rule twice

y/x + y'Ln(x) = xy'/y + ln(y)

then I would just solve for y'

am I doing any steps wrong?

- calculus -
**Damon**, Saturday, March 3, 2012 at 6:22pmI do not see anything wrong with the way you are going about it.

- calculus -
**Daniel**, Saturday, March 3, 2012 at 6:26pmAlright thanks