Homework Help: AP CHEMISTRY

Posted by DAN on Saturday, March 3, 2012 at 3:32pm.

A 1.00-L solution saturated at 25°C with lead(II) iodide contains 0.54 g of PbI2. Calculate the solubility-product constant for this salt at 25°C.

AP CHEMISTRY - DrBob222, Saturday, March 3, 2012 at 5:07pm
M PbI2 = moles/L.
mols = grams/molar mass
It is in 1 L. Calculate M and call this x.

PbI2(s) ===> Pb^2+ + 2I^-
...x.........x.........2x

Ksp = (Pb^2+)(I^-)^2
Substitute x for Pb^2+ and 2x for I^- (then square the I^-) and solve for Ksp.

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