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AP CHEMISTRY

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A 1.00-L solution saturated at 25°C with lead(II) iodide contains 0.54 g of PbI2. Calculate the solubility-product constant for this salt at 25°C.

  • AP CHEMISTRY - ,

    M PbI2 = moles/L.
    mols = grams/molar mass
    It is in 1 L. Calculate M and call this x.

    PbI2(s) ===> Pb^2+ + 2I^-
    ...x.........x.........2x

    Ksp = (Pb^2+)(I^-)^2
    Substitute x for Pb^2+ and 2x for I^- (then square the I^-) and solve for Ksp.

  • AP CHEMISTRY - ,

    6.4x10^-9

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