I wanted to calculate the normality of the acid and base solutions for a lab. But I'm extremely confused. I know normality is number of equivalents divided by volume in liters. But are we suppose to be given the number of equivalents of HCl and NaOH? Or are we suppose to figure out the number of equivalents? My lab teacher said that HCl is 0.1046 N but I wonder if this is equivalent.
HCl - volume (liters) = 0.01015 L
NaOH - volume (liters) = 0.01 L
From what you've said, I think the teacher has TOLD you that the HCl s/he has provided is 0.1046 N. And if you've used 10.15 mL (0.01015 L), the # equivalents of HCl is L x N = 0.1046 x 0.01015 = ?
Next, I assume you are to calculate the N of the NaOH listed next at 10 mL (0.01L).
Since we know that 1 equivalent of acid = 1 equivalent of base (actually = 1 equivalent of ANYTHING ELSE which is what make it nice when working with normality), then equivalents of the HCl above = equivalents of NaOH.
Since eq NaOH = L x N and we know equivalents NaOH and L NaOH, you can calculate the N or NaOH.
I obtained about 0.1062 N for NaOH.
Post a new question at the top of the page if I've misinterpreted your post.
No, I understand. Thank you very much
To calculate the normality of an acid or base solution, you need to know the number of equivalents and the volume in liters. The number of equivalents is determined by the chemical reaction that occurs when the acid or base dissociates in water.
In the case of hydrochloric acid (HCl), it dissociates completely in water to release one hydrogen ion (H+) and one chloride ion (Cl-). Since HCl is a monoprotic acid (donates only one proton), each mole of HCl provides one equivalent of acid.
In the information you provided, the volume of HCl is given as 0.01015 L. To calculate the normality of the HCl solution, you also need the number of equivalents. Since HCl is a monoprotic acid, the number of equivalents is equal to the number of moles. You can use the equation:
Number of moles = molarity × volume (in liters)
In this case, if you have been told that the HCl solution is 0.1046 N (normal), it means that 1 L of the solution contains 0.1046 equivalents. To find the number of equivalents in 0.01015 L of the HCl solution, you can use the following calculation:
Number of equivalents = 0.01015 L × 0.1046 N
So, you need to multiply the volume (in liters) by the normality to find the number of equivalents.
Similarly, for sodium hydroxide (NaOH), the number of equivalents can be determined by its chemical reaction. NaOH dissociates in water to release one hydroxide ion (OH-). Since NaOH is a monobasic base (accepts only one proton), each mole of NaOH provides one equivalent of base.
In the information you provided, the volume of NaOH is given as 0.01 L. To calculate the normality of the NaOH solution, you also need the number of equivalents. Just like in the case of HCl, you can use the equation:
Number of equivalents = volume (in liters) × normality
So, for NaOH, the calculation would be:
Number of equivalents = 0.01 L × normality
I hope this explanation helps you understand how to calculate the normality of acid and base solutions in your lab.