Homework Help: Physics help?

Posted by BOB on Saturday, March 3, 2012 at 9:17am.

A 170 -pF capacitor is connected in series with an unknown capacitance, and as a series combination they are connected to a battery with an emf of 25.0 V. If the 170 -pF capacitor stores 135 pC of charge on its plates, what is the unknown capacitance?

Physics help? - Henry, Sunday, March 4, 2012 at 6:30pm
Q1 = C1V1.
V1 = Q1/C1 = 135/170 = 0.794 Volts.

V2 = 25 - 0.794 = 24.206 Volts.
C2 = (0.794 / 24.206) * 170pF=5.576pF.

NOTE: The largest voltage appears across the smallest capacitor.

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