Posted by ogi on Saturday, March 3, 2012 at 7:08am.
2KOH + H2SO4 ==> H2SO4 + 2H2O
q = -56 kJ/mol KOH or 2-56 = -112 kJ/rxn.
50.0 mL x 0.500M KOH = 25 mmols.
25.0 mL x 0.500M H2SO4 = 12.5 mmols.
Total volume = 75 mL and I assume density is considered to be 1.00 g/mL.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
112 = 75g x 4.184 J/g*K x (Tfinal-22.8)
Solve for Tf
I get an estimate of 23+ C
Related Questions
Chem - When doing a limiting reagant problem, I need to determine to mole ratio...
chem - a.)How many moles of NaOH are required to prepare 2.00L od 0.380M ...
Chemisty (please read soon) - which will become a buffer in 1L of H2O? a) 0.3 ...
chemistry - how many ML of each of the following solutions will provide 25.0g of...
chemistry - This question I really don't get it. I tried tried tried to ...
math help - Thank you for helping me with the last problem Reiny and Bosnian. ...
Chemistry - Calculate the molarity of the following solutions: 5.0g of KOH in 4....
Chemistry - How many milliliters of 1.40 M KOH solution are needed to provide 0....
Chemistry - I don't know how to start this problem. Someone can help me ...
simple interest - What is the amount after 1 year on $315 invested at 7%, if ...
For Further Reading
