Tuesday
July 7, 2015

Homework Help: chemistry

Posted by ogi on Saturday, March 3, 2012 at 6:25am.

Nitroglycerin is a powerful explosive, giving four different gases when detonated.2 C3H5(NO3)3 (l) → 3 N2 (g) + 1/2 O2 (g) + 6 CO2 (g) + 5 H2O (g)Given that the enthalpy of formation of nitroglycerin, ΔHf°, is −364 kJ/mol, calculate the energy (heat at constant pressure) released by this reaction.Δ= Σn􀁄rxnHfΔ􀁄H(prod.) − ΣmfΔ􀁄H(reac.)= (3 mol)(0) + (1/2 mol)(0) + (6 mol)(−393.5 kJ/mol) + (5 mol)(−241.8 kJ/mol) − (2 mol)(−364 kJ/mol) rxnΔ􀁄H= −2842 kJ rxnΔ􀁄Hb) What is delta H when 4.65 mol of products is formed?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Members