February 20, 2017

Homework Help: Calculus. I need help!

Posted by MILY on Friday, March 2, 2012 at 10:17pm.

HARDER PARTS WAS 3(x^2+y^2)^2=26(y^2+y^2)

Find the equation of the tangent line to the curve (a lemniscate) 3(x^2+y^2)^2=26(y^2+y^2) at the point (-4,2). The equation of this tangent line can be written in the form y=mx+b where m is:? and where b is:?

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