Calculus ap
posted by lily .
Use implicit differentiation to find the slope of the tangent line to the curve XY^3 + XY = 5 at the point (3,2) .

3Y^2 x dy+ Y^3 dx+ x dy+ y dx=0
dy(3xy^2+x)=dx(y+y^3)
dy/dx= slope= (y^3+y)/(3xy^2+x)
put in the x,y and solve.
check my work, I did it in a hurry. 
i got the answer right thanks