Posted by lily on Friday, March 2, 2012 at 10:10pm.
3Y^2 x dy+ Y^3 dx+ x dy+ y dx=0
dy(3xy^2+x)=-dx(y+y^3)
dy/dx= slope= -(y^3+y)/(3xy^2+x)
put in the x,y and solve.
check my work, I did it in a hurry.
i got the answer right thanks
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