Posted by Kim on Friday, March 2, 2012 at 8:02pm.
Please use the same screen name for different posts.
.........NH3 + HOH ==> NH4^+ + OH^-
initial...x.............0.......0
change.-1.1E-3.........1.1E-3..1.1E-3
equil..x-1.1E-3........1.1E-3..1.1E-3
Kb = (NH3)(OH^-)/(NH3)
Substitute into the Kb expression and solve for x = (NH3)
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