Posted by Michael on Friday, March 2, 2012 at 4:05pm.
Find the absolute maximum and absolute minimum values of f on the given interval [π/4, 7π/4]. (Round all answers to two decimal places.)
f(t) = t + cot(t/2)

calculus  Steve, Friday, March 2, 2012 at 4:33pm
what's the problem?
f'(t) = 1  1/2 csc^2(t/2)
2 = csc^2(t/2)
√2 = csc(t/2)
csc pi/4,3pi/4 = √2
t/2 = pi/4 or 3pi/4
t = pi/2 or 3pi/2

calculus  Michael, Friday, March 2, 2012 at 6:56pm
Steve, thank you so much.
When plugging in the tvalues to find the f(t)'s, I mistakenly put in the t/2 points.
You cleared that right up for me. I owe you big time. Karma points.
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