Posted by **Michael** on Friday, March 2, 2012 at 4:05pm.

Find the absolute maximum and absolute minimum values of f on the given interval [π/4, 7π/4]. (Round all answers to two decimal places.)

f(t) = t + cot(t/2)

- calculus -
**Steve**, Friday, March 2, 2012 at 4:33pm
what's the problem?

f'(t) = 1 - 1/2 csc^2(t/2)

2 = csc^2(t/2)

√2 = csc(t/2)

csc pi/4,3pi/4 = √2

t/2 = pi/4 or 3pi/4

t = pi/2 or 3pi/2

- calculus -
**Michael**, Friday, March 2, 2012 at 6:56pm
Steve, thank you so much.

When plugging in the t-values to find the f(t)'s, I mistakenly put in the t/2 points.

You cleared that right up for me. I owe you big time. Karma points.

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