Posted by **airplanes** on Friday, March 2, 2012 at 3:50pm.

an airplane is flying 75km south and 35 km west of an airport. It is flying at a heigh of 6 km

A)what is the straight-line distance to the airport?

B)What is the angle of elevation of the airplane, from the point of of view of the airport?

- geometry -
**Steve**, Friday, March 2, 2012 at 4:56pm
The plane is at a distance d where

d^2 = 75^2+35^2+6^2 = 6886

d = 83 km (82.99, but who's checking?)

the angle of elevation θ = arctan(6/83) = 4.169° = 4°10'8"

- geometry - PS -
**Steve**, Friday, March 2, 2012 at 4:58pm
oops.

θ = arcsin(6/83) = 4.145°

- geometry -
**Anonymous**, Thursday, October 8, 2015 at 1:00am
θ = arcsin(6/83) = 4.145°

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