Posted by airplanes on Friday, March 2, 2012 at 3:50pm.
an airplane is flying 75km south and 35 km west of an airport. It is flying at a heigh of 6 km
A)what is the straightline distance to the airport?
B)What is the angle of elevation of the airplane, from the point of of view of the airport?

geometry  Steve, Friday, March 2, 2012 at 4:56pm
The plane is at a distance d where
d^2 = 75^2+35^2+6^2 = 6886
d = 83 km (82.99, but who's checking?)
the angle of elevation θ = arctan(6/83) = 4.169° = 4°10'8"

geometry  PS  Steve, Friday, March 2, 2012 at 4:58pm
oops.
θ = arcsin(6/83) = 4.145°

geometry  Anonymous, Thursday, October 8, 2015 at 1:00am
θ = arcsin(6/83) = 4.145°
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