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January 30, 2015

January 30, 2015

Posted by **Jasmine** on Friday, March 2, 2012 at 1:07pm.

I need to find the integral of that. So I separate the variables and have 1/y^2 dy = 4x dx. Where do I go from here?

- Calculus -
**Damon**, Friday, March 2, 2012 at 1:48pmy^-2 dy = 4 x dx

-1 y^-1 + c = 2 x^2 the important step

-1/y + c = 2 x^2

-1 + c y = 2 x^2 y

y (2 x^2 -c) = -1

y = -1/ (2 x^2 -c) you can write that several ways

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