posted by lissa .
A crate of oranges slides down an inclined plane without friction. If it is released from rest and reaches a speed of 4.883 m/s after sliding a distance of 2.01 m, what is the angle of inclination of the plane with respect to the horizontal? Please note: Give your answer in degrees!
v = a t
the AVERAGE speed is 2.4415 m/s
so t = 2.01 meters/2.4415 m/s = .823 seconds
4.883 = a (.823)
a = 5.93 m/s^2
F = m a
m g sin A = m (5.93)
9.81 sin A = 5.93
sin A = 5.93/9.81
solve inverse sin for A
ý did 5,93/9,81 = 0,604485219.... but it is false... what is the answer exactly
ok ok ok ok ý did. thanks... :D:D