Post a New Question


posted by .

A crate of oranges slides down an inclined plane without friction. If it is released from rest and reaches a speed of 4.883 m/s after sliding a distance of 2.01 m, what is the angle of inclination of the plane with respect to the horizontal? Please note: Give your answer in degrees!

  • physics -

    v = a t
    the AVERAGE speed is 2.4415 m/s
    so t = 2.01 meters/2.4415 m/s = .823 seconds

    4.883 = a (.823)
    a = 5.93 m/s^2

    F = m a
    m g sin A = m (5.93)

    9.81 sin A = 5.93
    sin A = 5.93/9.81
    solve inverse sin for A

  • physics -

    ý did 5,93/9,81 = 0,604485219.... but it is false... what is the answer exactly

  • physics -

    ok ok ok ok ý did. thanks... :D:D

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question