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December 20, 2014

December 20, 2014

Posted by **Diana** on Friday, March 2, 2012 at 10:16am.

f(x)= 2log(base2)X

- math -
**Dean**, Friday, March 2, 2012 at 12:51pmf(x) = y

y = 2log(base2)x

=log(base2)x^2

therefore

2^y=x^2

so x = sqrt(2^y)

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