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March 28, 2017

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also a problem that i cant figure out is how to do inverses of logs

f(x)= 2log(base2)X

  • math - ,

    f(x) = y
    y = 2log(base2)x
    =log(base2)x^2
    therefore
    2^y=x^2
    so x = sqrt(2^y)

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