Posted by **Angel** on Friday, March 2, 2012 at 9:15am.

Suppose a basketball player, Player A, made 80% of her free throw attempts last season and that she continues to shoot free throws at the same rate. Assume that free throw attempts are independent. Let the random variable X be the number of free throws that player A makes in her next 15 attempts.

a) What is the distribution of X?

b) Find the mean and standard deviation of X.

c) Find the probability that player A makes exactly 10 free throws.

d) Find the probability that player A makes at least 8 free throws.

- Statistics -
**MathGuru**, Friday, March 2, 2012 at 4:26pm
a) Binomial distribution

b) mean = np = 15 * .80 = ?

sd = √npq = √(15)(.80)(.20) = ?

Note: q = 1 - p

I'll let you finish the calculation.

c) Use a binomial probability table. n = 15, p = .80, x = 10

d) You can approximate a normal distribution by using z-scores.

Formula:

z = (x - mean)/sd

x = 8, mean & sd calculated from b) above.

Use a z-table to determine the probability using the z-score.

I hope this will help get you started.

## Answer this Question

## Related Questions

- Statistics - Suppose a basketball player, Player A, made 80% of her free throw ...
- statistics - Suppose a basketball player, Player A made 80% of her free throws ...
- Statistics - Suppose a basketball player is an excellent free throw shooter and ...
- math - Can someone please explain this to me I'm having a hard time solving it I...
- math - Suppose a basketball player is an excellent free throw shooter and makes ...
- mAtH - Suppose a basketball player is an excellent free throw shooter and makes ...
- statistics - Suppose a basketball player successfully makes 70% of the free ...
- Statistics and Probability - Suppose a basketball player successfully makes 70% ...
- statistics - a binomial distribution will be approximately correct as a model ...
- Statistics - Jamaal, a player on a college basketball team, made only 50% of his...

More Related Questions