Refering to reaction 2 H2(g) + O2(g) -> 2 H2O(g) and proving that the law of conservation of mass is obeyed during a chemical reaction.
I don't see a question here.
In any balanced chemical reaction, the number of atoms of each element present is the same on the reactant and product sides. Furthermore, the mass of each atom is unchanged by the reaction. The total number of electrons also does not change. Therefore mass is conserved.
To prove that the law of conservation of mass is obeyed during the chemical reaction of 2 H2(g) + O2(g) -> 2 H2O(g), we need to demonstrate that the total mass of the reactants equals the total mass of the products.
Let's break down the reaction step-by-step:
1. Start with the reactants: 2 H2(g) + O2(g)
- Hydrogen gas (H2) has a molar mass of 2 g/mol
- Oxygen gas (O2) has a molar mass of 32 g/mol
2. Calculate the total mass of the reactants:
- 2 molecules of H2 with a total mass of (2 g/mol) x (2 mol) = 4 grams
- 1 molecule of O2 with a mass of (32 g/mol) x (1 mol) = 32 grams
3. Now, let's move on to the products: 2 H2O(g)
- Water (H2O) has a molar mass of 18 g/mol
4. Calculate the total mass of the products:
- 2 molecules of H2O with a total mass of (18 g/mol) x (2 mol) = 36 grams
5. Finally, compare the total mass of the reactants with the total mass of the products:
- Total mass of reactants = 4 grams (from step 2)
- Total mass of products = 36 grams (from step 4)
As we can see, the total mass of the reactants (4 grams) is equal to the total mass of the products (36 grams). Therefore, the law of conservation of mass is followed in this reaction, confirming that mass is conserved during a chemical reaction.
To prove that the law of conservation of mass is obeyed during a chemical reaction, you need to demonstrate that the total mass of the reactants is equal to the total mass of the products. Let's break down the reaction you mentioned:
2 H2(g) + O2(g) -> 2 H2O(g)
This equation represents the reaction of hydrogen gas (H2) and oxygen gas (O2) to form water vapor (H2O).
Now, let's calculate the mass of the reactants and the mass of the products.
1. Calculate the mass of the reactants:
Since hydrogen gas (H2) is diatomic, its molar mass is 2 grams per mole.
The molar mass of oxygen gas (O2) is 32 grams per mole.
Given:
Number of moles of H2 = 2
Number of moles of O2 = 1
% Mass of H2 = 2 moles * 2 g/mole = 4 g
% Mass of O2 = 1 mole * 32 g/mole = 32 g
Total mass of the reactants = 4 g + 32 g = 36 g
2. Calculate the mass of the products:
Since water vapor (H2O) is diatomic, its molar mass is 18 grams per mole.
Given:
Number of moles of H2O = 2
% Mass of H2O = 2 moles * 18 g/mole = 36 g
Total mass of the products = 36 g
By comparing the total mass of the reactants (36 g) with the total mass of the products (36 g), we can see that they are equal. Therefore, the law of conservation of mass is obeyed in this chemical reaction.