Homework Help: Calculus

Posted by Jonathan on Friday, March 2, 2012 at 12:43am.

Sketch a possible graph for a function that has the following characteristics. f(0)=2.5

-horizontal asymptote is y=3
-Vertical x=4
-f'(x)<0 and f''(x)>0 for x>4.
-f'(x)<0 and f''(x) <0 for x<4

I got the horizontal and vertical but I don't know what to do for the last two.

Calculus - Steve, Friday, March 2, 2012 at 2:51pm
the asymptotes make

y = 3x/(x-4)

a good starting place. We want f to be falling on both sides of the asymptote, kind of like y=1/x.

y' = -12/(x-4)^2
y' < 0 on both sides of x=4

y'' = 24/(x-4)^3
y'' < 0 for x<4
y'' > 0 for x>4

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