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Chemistry

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Calculate the percent ionization of 0.120 M lactic acid (Ka=1.4*10^-4).

  • Chemistry - ,

    pH = pKa + log([A-]/[HA])

  • Chemistry - ,

    Let's call lactic acid HL.

    .........HL ==> H^+ + L^-
    initial.0.120....0.....0
    change...-x......x.....x
    equil...0.120-x...x....x

    Ka = 1.4E-4 = (H^+)(L^-)/(HL)
    Substitute from the ICE chart and solve for x which = (H^+). Then
    % ionization = [(H^+)/(0.120)]*100 = ?

  • Chemistry - ,

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