Homework Help: Physics

Posted by Loweri on Thursday, March 1, 2012 at 11:14pm.

Traveling at a speed of 16.3 m/s, the driver of an automobile suddenly locks the wheels by slamming on the brakes. The coefficient of kinetic friction between the tires and the road is 0.620. What is the speed of the automobile after 1.60 s have elapsed? Ignore the effects of air resistance.

Physics - drwls, Friday, March 2, 2012 at 5:19am
Deceleration rate
a = (friction force)/mass
= M g 0.62/M = 0.62 g = 6.08 m/s^2

After t = 1.60 s,

V = Vo - a*t = 16.3 - 6.08*1.60
= 6.57 m/s

Answer this Question

Related Questions

College Physics - Speed - Traveling at a speed of 15.6 m/s, the driver of an ...
Physics - Traveling at a speed of 20.0 m/s, the driver of an automobile suddenly...
Physics - Traveling at a speed of 15.9 m/s, the driver of an automobile suddenly...
Physics - Traveling at a speed of 19.3 m/s, the driver of an automobile suddenly...
physics - Traveling at a speed of 18.3 m/s, the driver of an automobile suddenly...
physics - Traveling at a speed of 18.5 m/s, the driver of an automobile suddenly...
physics - Traveling at a speed of 14.3 m/s, the driver of an automobile suddenly...
Physics - Traveling at a speed of 16.1 m/s, the driver of an automobile suddenly...
physics - Consult Multiple Concept Example 10 in preparation for this problem. ...
Physics - THIS IS DUE TMRW PLEASE HELP! - The left and right wheels of an ...

For Further Reading

First Name:
School Subject:
Answer: