5x-2y=4
x+2y=8
if you are trying to solve for the variables subtract 2y to the other side so you then have X=-2y +8 for the equation and put it in for x in the top equation
5(-2y+8) -2y=4
-10y+40-2y=4
-12y=-36
y=3
so then put 3 in for the bottom equation
x+2(3)=8
x=2
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Sorry, got carried away/ Yes u do put 3 in the bottom of the equation. oh yes... mmm, right.
To solve this system of equations, we can use the method of elimination. This involves getting rid of one of the variables by adding or subtracting the equations.
First, let's multiply the second equation by -1 to make the y coefficients have opposite signs:
-1(x + 2y) = -1(8)
- x - 2y = -8
Now, let's add the two equations together to eliminate the y variable:
(5x - 2y) + (-x - 2y) = 4 + (-8)
5x - 2y - x - 2y = 4 - 8
Simplifying, we get:
4x - 4y = -4
Dividing both sides of this equation by 4, we get:
x - y = -1
This equation can be used to substitute for x in either of the original equations. Let's use the first equation:
5x - 2y = 4
Substituting for x, we get:
5(-1 + y) - 2y = 4
Simplifying this equation, we get:
-5 + 5y - 2y = 4
3y - 5 = 4
Adding 5 to both sides, we get:
3y = 9
Dividing both sides by 3, we get:
y = 3
Now that we have the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the second equation:
x + 2y = 8
Substituting for y, we get:
x + 2(3) = 8
Simplifying this equation, we get:
x + 6 = 8
Subtracting 6 from both sides, we get:
x = 2
Therefore, the solution to the system of equations is x = 2 and y = 3.