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August 21, 2014

August 21, 2014

Posted by **anonymous** on Thursday, March 1, 2012 at 6:33pm.

of ice at −6 C to melt it and raise the temperature of the water to 61 C? The specific heat of ice is 0.49 kcal/kg · K and of water is 1 kcal/kg · K; the heat of fusion of water is 79.7 kcal/kg, and its heat of vaporization is 418 kcal/kg.

Answer in units of kcal

- chemistry -
**DrBob222**, Thursday, March 1, 2012 at 9:46pmUse two formulas.

Within a phase:

q=mass x specific heat x (Tfinal-Tinitial)

phase change:

mass x heat vap at boiling point

mass x heat fusion at melting point

For example:

at melting point of ice. To change solid ice at zero C to liquid at zero C.

q = 59 g ice x heat fusion - 59 x 80 cal/g = ?

From ice at zero to water 100 C

q = mass x specific heat x(Tfinal-Tinitial) = 59 g x 1 cal/g x (100-0) = ?

Then add all of the q amount to obtain total q the divide by 1000 to convert to Kcal.

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