Tuesday

August 30, 2016
Posted by **michelle** on Thursday, March 1, 2012 at 5:53pm.

- Math please help urgent ! -
**Damon**, Thursday, March 1, 2012 at 6:25pmdy/dx = dy/du du/dx

du/dx = (1/3)x^-(2/3)

dy/du = [(u-1)-(u+3)]/(u-1)^2

= [(x^(1/3)-1)-(x^(1/3)+3)/(x^(1/3)-1)^2

= -4 / (x^(2/3) -2x^(1/3)+1)

so

dy/du * du/dx

=(-4/3)(x^-(2/3)) /(x^(2/3) -2x^(1/3)+1)

= -4/3(x^4/3-2x +x^(2/3)) - Math please help urgent ! -
**Damon**, Thursday, March 1, 2012 at 6:28pmluckily 8^(1/3) = 2 :)