pete colored 1/2 of a poster. rebecca colored 1/3 of the poster. what fraction still needs to be colored?

1/2 = 3/6

1/3 = 2/6

3/6 + 2/6 = 5/6

6/6 - 5/6 = ?

To find out the fraction that still needs to be colored, we need to determine the fraction that Pete and Rebecca have already colored and subtract it from the whole poster.

Let's calculate each person's coloring fraction first:

Pete colored 1/2 of the poster.
Rebecca colored 1/3 of the poster.

Now, we need to add their fractions together:

1/2 + 1/3

To add these fractions, we need to find a common denominator.

The least common multiple (LCM) of 2 and 3 is 6.

So, let's rewrite the fractions with the common denominator of 6:

(3/6) + (2/6) = 5/6

Now, we have the fraction that Pete and Rebecca colored together.

To find the fraction that still needs to be colored, we need to subtract this fraction from 1 (whole poster):

1 - 5/6

To subtract these fractions, we also need a common denominator of 6:

(6/6) - (5/6) = 1/6

So, the fraction that still needs to be colored is 1/6 of the poster.

To find the fraction that still needs to be colored, we need to subtract the fractions that Pete and Rebecca have already colored from the total area of the poster.

Let's start by finding the fraction colored by Pete. Given that Pete colored 1/2 of the poster, the fraction colored by Pete is 1/2.

Next, let's determine the fraction colored by Rebecca. Given that Rebecca colored 1/3 of the poster, the fraction colored by Rebecca is 1/3.

To find the total area of the poster, we add the fractions that Pete and Rebecca colored: 1/2 + 1/3.

To add these fractions, we first need to find a common denominator. The least common multiple (LCM) of 2 and 3 is 6. Therefore, we can rewrite the fractions with a common denominator of 6:

1/2 = 3/6
1/3 = 2/6

Now we can add these fractions:

3/6 + 2/6 = 5/6

So, the fraction already colored by Pete and Rebecca combined is 5/6.

To find the fraction that still needs to be colored, we subtract the combined fraction (5/6) from the total area of the poster (1):

1 - 5/6

To subtract these fractions, we also need a common denominator:

1 = 6/6

Now we can subtract the fractions:

6/6 - 5/6 = 1/6

Therefore, the fraction that still needs to be colored is 1/6 of the poster.