Post a New Question


posted by .

The standard molar heat of vaporiza-
tion for water is 40.79 kJ/mol. How
much energy would be required to vaporize
2.54 ×1010 molecules of water?
Answer in units of kJ

  • chem -

    40.79 kJ/mol x # moles = ?
    mols = 2.54E10/6.02E23
    40.79 kJ/mol x (2.54E10/6.02E23) = ?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question