To get 8, what operations (+ - x / sqrt) do I use between a series of four 3s (3_3_3_3=8)?
3x3 - 3/3
To get 8 using a series of four 3s, you can use the following operations:
3 + 3 + 3 - 3 = 8
So, just add three 3s together and then subtract one. Voila! You've got 8. Though I must admit, using math to summon the number 8 from a bunch of 3s is a bit like juggling bananas while riding a unicycle. It's not the most elegant solution, but it gets the job done with a touch of clownish flair!
To achieve a result of 8 using four 3s, you can use the following set of operations:
1. Subtract 3 from 3, which gives you 0.
2. Divide 3 by 3, which gives you 1.
3. Add 3 to 3, which gives you 6.
4. Add 6 and 1, which results in 7.
5. Finally, add 7 and 1, which gives you the desired result of 8.
Therefore, the sequence of operations would be: - / + + = 8
To obtain 8 using a series of four 3s with the given operations, you can try different combinations. Here are a few solutions:
1. Addition and Division:
- Divide the first 3 by the second 3: 3 ÷ 3 = 1
- Add the third 3: 1 + 3 = 4
- Divide the result by the fourth 3: 4 ÷ 3 = 1.33 (approximately)
- Subtract this from 3: 3 - 1.33 = 1.67 (approximately)
- Take the square root of the previous result: sqrt(1.67) ≈ 1.29 (approximately)
2. Subtraction and Square Root:
- Subtract the first 3 from the second 3: 3 - 3 = 0
- Square root of the third 3: sqrt(3) ≈ 1.73 (approximately)
- Add the fourth 3: 1.73 + 3 = 4.73 (approximately)
- Subtract this from 3: 3 - 4.73 ≈ -1.73 (approximately)
- Take the square root of the previous result: sqrt(-1.73) (not possible as it involves the square root of a negative number)
3. Multiplication and Square Root:
- Multiply the first 3 by the second 3: 3 x 3 = 9
- Divide this by the third 3: 9 ÷ 3 = 3
- Subtract the fourth 3: 3 - 3 = 0
- Take the square root of the previous result: sqrt(0) = 0
As you can see, there are multiple ways to combine the operations to obtain the value 8.