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April 18, 2014

April 18, 2014

Posted by **Sanjay** on Thursday, March 1, 2012 at 4:44pm.

- Math -
**MathMate**, Thursday, March 1, 2012 at 7:24pmLet A be (0,0).

B is then (0,10)

C is 10 km at 060 from B.

Bearings are measured from north in a clockwise direction, which means that C is 10 km at 30° north of east.

So C is at

(0+10cos(30), 10+10sin(30))

=(10+(√3)/2 , 10+10/2)

=(10+(√3)/2 , 15)

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